Mass guild whisp for X rang.
 

Hello everybody!

This is ma script:

/run for i = 1, select(2, GetNumGuildMembers()) do SendChatMessage("TEXT MESSAGE", "WHISPER", nil, GetGuildRosterInfo(i)) end


So.. how to change the script so that will not whisp all the people who are online, but whisp only to a XXX rank in the guild?

Like..

*Member* - nothing whisp!
*Veteran* - nothing whisp!
*Newbie* - Hello, this is.. blahblahblah!

Thx you!

try this

/run for i = 1, select(2, GetNumGuildMembers()) do SendChatMessage("TEXT MESSAGE", "WHISPER", nil, GetGuildRosterInfo(i), GuildControlGetRankName("rank name")) end

It might work, I'm not playing WoW atm so I can't test it.

Nope, dosnt work :)

I think need put rang level.

http://www.wowwiki.com/API_GuildControlGetRankName

tinyu: that's not how SendChatMessage() works, nor is it what GuildControlGetRankName() is for. ;)

makaka: This is untested, but really should work. ;)
GetGuildRosterInfo has many returns. The first is name, and the second is rank. As your script goes through the loop, it assigns that member's name to the variable n and their rank to the variable r. If the rank is "Newbie" (or whatever you want to replace that with) then it will send the message. I also tightened it up a little bit more. As written, if your rank name is "Newbie" or another 6-letter name, you have 114 characters to use for your message.

cheers Seerah I was just making a stab in the dark I was almost certain what I posted was wrong lol.

Tryed, but doesn't work. I think need change r="Newbie" - r="(number of rank)". I use russian client, and maybe it did not work because of transliteration, but I changed the name of the rank from Russian to English name - Newbie. And this again dsoen't work.

No, the second return of GetGuildRosterInfo() is a string - the actual name of the rank. http://wowprogramming.com/docs/api/GetGuildRosterInfo

Is Newbie the actual name of the rank you want to check for? I noted that you need to replace that with whatever you're looking for.

Also, to test for equality, you need two equals-signs, not one.

This sets the value of r to "Newbie", and the check fails because setting a variable doesn't return anything:

if r = "Newbie" then

This compares the value of r to "Newbie" and returns true (passing the check) if it is:

if r == "Newbie" then

There we go! I don't know how I missed that twice. :o