Need help for a Lua Text Code

XoL · 05-31-10, 01:12 PM

Hey Guys,

im searching for a lua text help.

What i want to do is a text With current hp and percent hp IF ! percent hp is lower than 100.

It should look like this in the unit frame :

24.k ( If 100% )
23.0k | 90 % (if 90%)

can anybody help me ?

NitraMo · 05-31-10, 03:04 PM

This code should produce the desired output:

(math.floor(UnitHealth("player")/100+0.5)/10).."k"..(UnitHealthMax("player")>UnitHealth("player") and " | "..(math.floor(UnitHealth("player")/UnitHealthMax("player")*100+0.5)).."%" or "")

If you want decimals on the percentage, see the green text. Add one 0 on each of those two numbers for each extra decimal you want, this one got one decimal

(math.floor(UnitHealth("player")/100+0.5)/10).."k"..(UnitHealthMax("player")>UnitHealth("player") and " | "..(math.floor(UnitHealth("player")/UnitHealthMax("player")*1000+0.5)/10).."%" or "")