Sorting

[Resike]

So i have a table like this:

        local Position = { }
	for i = 1, 5 do
		Position[i] = {Texture = nil, Offset = nil}
		Position[i].Texture = i
		Position[i].Offset = lolobject[i]:GetLeft()
		print(Position[i].Texture, Position[i].Offset)
	end

Is there any way i can sort it based on Offset, without the hard way?

[Torhal]

Originally Posted by Resike So i have a table like this: local Position = { } for i = 1, 5 do Position[i] = {Texture = nil, Offset = nil} Position[i].Texture = i Position[i].Offset = lolobject[i]:GetLeft() print(Position[i].Texture, Position[i].Offset) end Is there any way i can sort it based on Offset, without the hard way?

local function SortByOffset(a, b)
    return a.Offset < b.Offset
end

        local Position = { }
	for i = 1, 5 do
		Position[i] = {Texture = nil, Offset = nil}
		Position[i].Texture = i
		Position[i].Offset = lolobject[i]:GetLeft()
		print(Position[i].Texture, Position[i].Offset)
	end

        table.sort(Position, SortByOffset)

[Resike]

Originally Posted by Torhal local function SortByOffset(a, b) return a.Offset < b.Offset end local Position = { } for i = 1, 5 do Position[i] = {Texture = nil, Offset = nil} Position[i].Texture = i Position[i].Offset = lolobject[i]:GetLeft() print(Position[i].Texture, Position[i].Offset) end table.sort(Position, SortByOffset)

Awsome thanks, i managed to do it in another but very similar way, but i like to name the variables inside tables so i'll stick with this one. But i'll post mine too, maybe someone can use it.

        local Position = { }
	for i = 1, 5 do
		Position[i] = { }
		Position[i][1] = i
		Position[i][2] = lolobject[i]:GetLeft()
	end
	table.sort(Position, function(a, b) return a[2] > b[2] end)
        for k, v in ipairs(Position) do
		print(v[1], v[2])
	end

[Torhal]

You'll note that I declared my sort function outside the scope of the table.sort() call to avoid re-creating the function every time I needed to sort the table.

[Resike]

Originally Posted by Torhal You'll note that I declared my sort function outside the scope of the table.sort() call to avoid re-creating the function every time I needed to sort the table.

Yep i'll do that too later, since i'm gonna call that comparing function more time.

[Resike]

Originally Posted by Torhal You'll note that I declared my sort function outside the scope of the table.sort() call to avoid re-creating the function every time I needed to sort the table.

If i call the function from the talbe.sort like that, it doesn't pass the "a, b" arguments. Also tried it with:

table.sort(Position, SortByOffset(a,b))

same stuff.

[p3lim]

Originally Posted by Resike If i call the function from the talbe.sort like that, it doesn't pass the "a, b" arguments. Also tried it with: table.sort(Position, SortByOffset(a,b)) same stuff.

That would be an invalid syntax and you'd get an error, use this:

table.sort(Position, SortByOffset)

[ravagernl]

Originally Posted by Resike If i call the function from the talbe.sort like that, it doesn't pass the "a, b" arguments. Also tried it with: table.sort(Position, SortByOffset(a,b)) same stuff.

You're passing the result of the function "SortByOffset" on two variables(a and b), which are probably nil because they are not set in that scope. In addition, table.sort will throw an error if a and b do exist because table.sort expects the variable to be a function to run for each comparison.

[Resike]

Originally Posted by p3lim That would be an invalid syntax and you'd get an error, use this: table.sort(Position, SortByOffset)

I also tried that but didn't worked, however is't working now, not sure what was wrong with it in the first place.